Orthogonal comparisons (5 of 5)

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For this example,

L1 = (2)(4)+ (-1)(3) + (-1)(2) = 3



SSB1 = 3²/1.5 = 6

L2 = (0)(4)+ (1)(3) + (-1)(2) = 1





SSB2 = 1²/.5 = 2

SSB = SSB1 + SSB2 = 6 + 2 = 8 which is the same value obtained in the analysis of variance.

It is important to know whether the comparisons you are conducting are orthogonal or not. However, it is not critical that you limit yourself to orthogonal comparisons. It is much more important to test the comparisons that make sense in terms of your experimental hypotheses.


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