Confidence Interval on Linear Combination of Means, Independent Groups (3 of 5)
They are:
Maspirin= 4
MTylenol= 3, and
Mplacebo = 2.
L can now be computed as: L = (.5)(4) + (.5)(3) + (-1)(2) = 1.5.
The estimated value of
is
therefore 1.5.In order to compute MSE, it is necessary to compute s² for each group. The values are: 1.334, 1.334, and 0.666. Therefore,
MSE = (1.334 + 1.334 + 0.666)/3 = 1.111.
Σa² =[.5² + .5² + (-1)²] = 1.5
Since there are four subjects in each group, n = 4
The component parts of s are now computed:
