Trend Analysis (4 of 5)

Assume that the MSE for the magnitude of reward experiment were 5 and that there were 10 subjects per group. The group means are:

Reward size   Time
    2          10
    4           6
    6           4
    8           3

The table on the previous page shows that the coefficients for the linear component of trend with four groups are:

-3, -1, 1, 3.

Applying the formulas for a comparison presented elsewhere:

L = ΣM_ia_i = (10)(-3) + (6)(-1) + (4)(1) +(3)(3) = -23

standard error of L

= 3.162.

t = -23/3.162 = -7.27.