# All Pairwise Comparisons among Means: Newman-Keuls Procedure (3 of 4)

Since the comparison at span 5 is significant, the following two comparisons are made at span 4 using the lower critical value of t of 3.96:

Mean 1 versus Mean 4
Mean 2 versus Mean 5

The t for Mean 1 versus Mean 4 is 3.27, which is not significant. Therefore, no further comparisons within the span are performed and the following comparisons are deemed non significant:
Mean 1 versus Mean 2
Mean 1 versus Mean 3
Mean 1 versus Mean 4
Mean 2 versus Mean 3
Mean 2 versus Mean 4
Mean 3 versus Mean 4
The t for Mean 2 versus Mean 5 is 5.71 which is higher than the critical value for a span of four of 3.96. Since the comparison of Means 2 and 5 is significant, comparisons of span 3 within this span that were not previously ruled out are performed. Since the comparison of Means 2 and 4 is ruled out by the failure of the comparison of Means 1 and 4 to be significant, the only comparison that is done is between Means 3 and 5. The value of t is 4.49 which is higher than the critical value for span 3 of 3.58.