SSE = SSE

df = n

MSE = SSE/df = 26/7 = 3.71

The p value associated with a t of 0.77 with 7 df is 0.47. Therefore, the difference between groups is not significant.

- Specify the null hypothesis and an alternative hypothesis.

- Compute M
_{d}= M_{1}- M_{2}

- Compute SSE
_{1}= Σ(X - M_{1})² for Group 1 and SSE_{2}= Σ(X -M_{2})² for Group 2

- Compute SSE = SSE
_{1}+ SSE_{2}

- Compute df = N - 2 where N = n
_{1}+ n_{2}

- Compute MSE = SSE/df

- Compute:

(If the sample sizes are equal then n_{h }= n_{1}= n_{2}).

- Compute:

- Compute:

where µ_{1}- µ_{2}is the difference between population means specified by the null hypothesis (and is usually 0).

- Use a t table to compute p from t (step 9) and df (step 5).